Bragg's Equation
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Calculate the distance between the planes of ions if the smallest angle of reflection is x-ray diffraction is 5.970 and the wavelength of incident ray is 58.6 pm? (sin5.970 = 0.104)
282 pm
382 pm
156 pm
78 pm
In the Bragg's equation for diffraction of X-rays, n represents for
[MP PMT 2000]
Quantum number
An integer
Avogadro's numbers
Moles
The second order Bragg diffraction of X-rays with l =1.0 A0 froma set of parallel planes in a metal occurs at an angle of 600.The distance between the scattering planes in the crystal is
0.575 A0
1.00 A0
2.00 A0
1.15 A0
First order X-ray reflection (λ = 154 pm) is maximum from a set of (2, 0, 0) planes of a B.C.C lattice was observed at 16∘, 6’. Then, the edge length of unit cell is
360 pm
420 pm
560 pm
180 pm
In Bragg’s equation n λ = 2 d sinθ, ‘n’ represents
the number of moles
the principal quantum number
the Avogadro’s number
the order of reflection
What is the wavelength of x-ray, if the interplanar distance of the crystal is 286 pm and the incident angle is 15.8o. Order of reflection is 2.
378 pm
154.2 pm
294.3 pm
77.8 pm
- 0.575 ∘A
- 1.00 ∘A
- 2.00 ∘A
- 1.15 ∘A