Entropy Change in Isobaric Process
Trending Questions
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
None of these
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q. Find out the change in entropy ΔS in J K−1 when 4 mol of Helium gas is isobarically heated from 250 K to 350 K.
Assume Cp, m=5.19 kJ mol−1 K−1
Assume Cp, m=5.19 kJ mol−1 K−1
- 4812
- 3950
- 6989
- 7050
Q.
Which of the following is the correct expression of ΔS for an isobaric process?
ΔS=nCPln T2T1+nR ln V2V1
ΔS=nCp lnT2T1
ΔS=nCp lnT1T2
None of these