Derivation of Kp and Kc
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NO2(g)⇌12N2(g)+O2(g) ⋯K1
N2O4(g)⇌2NO2(g) ⋯K2
Give the expression for equilibrium constant for the formation of N2O4 from N2 and O2:
- 12K1+1K2
- √1K1K2
- K2K1
- 1K21×1K2
Consider the following equilibrium in a closed container:
N2O4 (g) ⇋ 2NO2 (g)
At a fixed temperature, the volume of the reaction container is halved. For this change, which of the following statements holds true regarding the equilibrium constant Kp and degree of dissociation α?
both
and
changes
changes, but
does not change
does not change, but
changes
neither
nor
changes
The thermal decomposition of N2O4g) ⇋ 2NO2 (g) is as shown below:
N2O4(g)⇌2NO2(g)At starta mol 0 molAt equb.(a−x)mol 2x mol
Where x = degree of dissociation. If V and P are equilibrium volume and pressure respectively then the corresponding expressions for Kc and Kp are 4x2V(a−x) and 4x2a2−x2 (respectively). True or False?
True
False
For the reaction 2NH3 (g) ⇌ N2(g) + 3H2(g), if the total equilibrium pressure is P and degree of dissociation is α, the equilibrium constant Kp is given by
27α4p216(1−α2)2
True
False
2PQ⇋ P2+Q2;K1=2.5× 105
PQ+12R2⇋ PQR, K2=5× 10−3
The value of K3 for the equilibrium
1/2 P2+1/2Q2+1/2 R2 ⇋ PQR
- 2.5 x 10-3
- 2.5 x 103
- 1.0 x 10-5
- 5 x 103
4A + 5B⇋ 4P+6Q,
The equilibrium constant Kc has units
- mol L-1
- mol-1L
- unit less
- (mol L-1)-2
At 298 K and 1 atm pressure, the partial pressures in an equilibrium mixture of N2O4 and NO2 are 0.7 and 0.3 atmosphere respectively. What will be the partial pressure of NO2 when the gases are in equilibrium at 298 K and at a total (equilibrium) pressure of 10 atmospheres?
2.23 atm
1.078 atm
1.60 atm
0.77 atm
- 0.0199
- 1.99
- 0.282
- 0.0796
- 0.147
- 0.026
- 0.05
- 0.073
The equilibrium constant kc of the reaction A2 (g) + B2 (g) ⇌ 2AB (g) is 50. If 1 mol of A2 and 2 mol of B2 are mixed, the amount of AB at equilibrium would be:
.934 mol
.467 mol
1.4 mol
1.867 mol