Equivalent, Molar Conductivity and Cell Constant

Q. Molar conductivity of $0.01MC{H}_{3}COOH$ at certain temperature is $38.93Sc{m}^{2}mo{l}^{-1}$. What is its pH?
$[{\lambda }_{H^{+}}^0=349.6Sc{m}^2,{\lambda }^{0}C{H}_{2}COO=78.1Sc{m}^{2}mo{l}^{-1}$ and $log9=0.96]$
(Round off to the nearest integer)

Q. The resistance of 0.01 N solution of an electrolyte is 210 $\Omega$ at 298 K with a cell constant of 0.88 $c{m}^{-1}$. Calculate the conductivity and equivalent conductivity of the solution.

1. $7.19\times {10}^{-3}oh{m}^{-1}c{m}^{-1},719.05Sc{m}^{2}e{q}^{-1}$
2. $4.19\times {10}^{-3}oh{m}^{-1}c{m}^{-1},419.05Sc{m}^{2}e{q}^{-1}$
3. $5.19\times {10}^{-3}oh{m}^{-1}c{m}^{-1},519.05Sc{m}^{2}e{q}^{-1}$
4. $6.19\times {10}^{-3}oh{m}^{-1}c{m}^{-1},619.05Sc{m}^{2}e{q}^{-1}$

Q. The electrical resistance of a column of 0.05 M NaOH solution of diameter 1 cm and length 50 cm is $5.55\times {10}^3$ ohm. Calculate its resistivity, conductivity, and molar conductivity.

1. $87.135\times {10}^{-2}ohmm,1.148S{m}^{-1},229.6\times {10}^{-4}S{m}^{2}mo{l}^{-1}$
2. $67.135\times {10}^{-2}ohmm,1.489S{m}^{-1},229.6\times {10}^{-4}S{m}^{2}mo{l}^{-1}$
3. $87.135\times {10}^{-2}ohmm,1.296S{m}^{-1},229.6\times {10}^{-4}S{m}^{2}mo{l}^{-1}$
4. $77.135\times {10}^{-2}ohmm,1.148S{m}^{-1},229.6\times {10}^{-4}S{m}^{2}mo{l}^{-1}$

Q.

Conductivity (unit Siemens) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length of the vessel then the unit of the constant of proportionality is

[AIEEE 2002]

1. 
   

2. 
   

3. 
   

4. 
   

Q.

In infinite dilutions, the molar conductances of Ba²⁺ and Cl^- are 127 and

76 . The equivalent conductivity of at infinite

dilution is

[CBSE 2000]

1. 101.5

2. 139.5

3. 279.5

4. 203.5

Q. The molar ionic conductances at infinite dilution of $M{g}^{2+}$ and $C{l}^{-}$ are 106.1 and 76.3 $oh{m}^{-1}oh{m}^{-1}c{m}^{2}mo{l}^{-1}$ respectively. The Molar conductance of solution of $MgC{l}_2$ at
infinite dilution is

1. $285.7oh{m}^{-1}c{m}^{2}mo{l}^{-1}$
2. $258.7oh{m}^{-1}c{m}^{2}mo{l}^{-1}$
3. $29.8oh{m}^{-1}c{m}^{2}mo{l}^{-1}$
4. $183.4oh{m}^{-1}c{m}^{2}mo{l}^{-1}$

Q. The resistance and conductivity of 0.02 M KCl solution are 82.4 ohm and $0.002768Sc{m}^{-1}$, respectively. When filled with $0.005N{K}_{2}S{O}_4$, the solution had a resistance of 324 ohm. Calculate equivalent conductivity of $K_{2}S{O}_4$ solution.

1. $581.6Sc{m}^{2}mo{l}^{-1}$
2. $681.6Sc{m}^{2}mo{l}^{-1}$
3. $281.6Sc{m}^{2}mo{l}^{-1}$
4. $381.6Sc{m}^{2}mo{l}^{-1}$

Q. Cell constant is

1. $\frac{a}{l}$
2. $\rho \frac{l}{a}$
3. $\frac{l}{a}$
4. $\frac{a^2}{l}$

Q. The resistance of decinormal solution of a salt occupying a volume between two platinum electrodes 1.80 cm apart and 5.4 $c{m}^2$ area was found to be 32 ohm. Calculate ${\wedge }_{eq}$.

1. $114.1Sc{m}^{2}e{q}^{-1}$
2. $124.1Sc{m}^{2}e{q}^{-1}$
3. $104.1Sc{m}^{2}e{q}^{-1}$
4. $134.1Sc{m}^{2}e{q}^{-1}$

Q. Equivalent conductivity ${\wedge }_{eq}$

1. $\frac{k\times 1000}{N}oh{m}^{-1}c{m}^{2}E{q}^{-1},N-normality$
2. None of the above
3. $\frac{k\times 1000}{M}oh{m}^{-1}c{m}^{2}E{q}^{-1},M-molarity$
4. $\frac{k\times 1000}{m}oh{m}^{-1}c{m}^{2}E{q}^{-1},m-molality$