Complex Numbers
Trending Questions
Q.
a + ib > c + id can be explained only when
a = 0, c = 0
b = 0, c = 0
b = 0, d = 0
a = 0, d = 0
Q. The value of (1+i)8+(1−i)8 is
[RPET 2001; KCET 2001]
[RPET 2001; KCET 2001]
16
- -32
- 32
- -16
Q. The value of (1+i)6+(1−i)6 is
[RPET 2002]
[RPET 2002]
0
27
26
- None of these
Q. Let α, β be real and z be a complex number. If z2+αz+β=0 has two distinct roots on the line Re(z)=1, then it is necessary that
- β ϵ (1, ∞)
- β ϵ (0, 1)
- |β|=1
- β ϵ (−1, 0)
Q. Let z=x+iy be a complex number such that |z|=1, where i=√−1. Match List - I with List - II.
List-IList - II(I)Re(iz1+z2) is equal to(P) 0(II)Im(iz1+z2) can be equal to(Q) 1(III)Number of integers NOT in the(R) 12range of Im(iz1+z2) is equal to(IV)12πarg(iz1+z2) is equal to(S)−12(where−π<arg(z)≤π)(T)−14(U) 14
Which of the following is only CORRECT combination?
List-IList - II(I)Re(iz1+z2) is equal to(P) 0(II)Im(iz1+z2) can be equal to(Q) 1(III)Number of integers NOT in the(R) 12range of Im(iz1+z2) is equal to(IV)12πarg(iz1+z2) is equal to(S)−12(where−π<arg(z)≤π)(T)−14(U) 14
Which of the following is only CORRECT combination?
- I→P, Q
- I→P, Q, R
- II→Q, R, S
- III→Q, R
Q. Let z=x+iy be a complex number such that |z|=1, where i=√−1. Match List - I with List - II.
List-IList - II(I)Re(iz1+z2) is equal to(P) 0(II)Im(iz1+z2) can be equal to(Q) 1(III)Number of integers NOT in the(R) 12range of Im(iz1+z2) is equal to(IV)12πarg(iz1+z2) is equal to(S)−12(where−π<arg(z)≤π)(T)−14(U) 14
Which of the following is only CORRECT combination?
List-IList - II(I)Re(iz1+z2) is equal to(P) 0(II)Im(iz1+z2) can be equal to(Q) 1(III)Number of integers NOT in the(R) 12range of Im(iz1+z2) is equal to(IV)12πarg(iz1+z2) is equal to(S)−12(where−π<arg(z)≤π)(T)−14(U) 14
Which of the following is only CORRECT combination?
- III→P, Q
- IV→T, U
- III→P, Q, T
- III→S, T, U
Q. Let z be a complex number satisfying the equation z2−(3+i)z+m+2i=0, where m∈R. Suppose the equation has a real root. The additive inverse of non-real root, is
- −1−i
- 1+i
- 1−i
- −2
Q. The complex number 2n(1+i)2n+(1+i)2n2n, n∈I is equal to
- 2
- {1+(−1)n}⋅in
- 0
- {1−(−1)n}⋅in
Q. Quadratic equation x2+(a−1)ix+5=0 (a∈R) will have a pair of conjugate complex roots, if
- a=1
- a2−2a+21>0
- a2−2a+21<0
- a2+2a−21>0
Q. If a<0, b>0, then √a⋅√b is equal to
- −√|a|⋅b
- √|a|b
- √|a|⋅b⋅i
- None of the above