Descarte's Rule for Positive Roots
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Q.
If the cube roots of unity are then the roots of the equation are
None of these
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If the sum of two roots of is zero, then is equal to
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How do you find all roots?
Q. By Descartes rule of sign, the maximum number of positive real roots of equation x5−6x4+7x3+8x2+9x+10=0
Q. Select the correct statements for the equation x5+4x4−3x2+x−6=0.
- The number of negative roots can be 0
- The number of negative roots can be 2
- The number of negative roots can be 1
- The number of negative roots can be 3
Q. Consider the cubic equation x3−4x2+x+6=0
Statement 1: Equation has 2 Positive real roots, 1 Negative real root
Statement 2: Equation has 1 Negative real root, 2 Imaginary roots.
Statement 1: Equation has 2 Positive real roots, 1 Negative real root
Statement 2: Equation has 1 Negative real root, 2 Imaginary roots.
- Possibility no. 1
- Possibility no. 2
- Both of the above
Q. Using Descartes Rule of Signs, the maximum possible no. of real roots for f(x)=x3−8x2−9x+12 is:
- No. of positive real roots can be 1
- No. of positive real roots can be 2
- No. of real roots can be 3
- No. of negative real roots can be 2
Q. The mximum number of real roots of the equation f(x)=x6+8x2−14x+1 is
- 0
- 6
- 2
- 1
Q. Using Descartes Rule of Signs, the maximum possible no. of real roots for f(x)=x5−6x2−4x+5 is:
- 0
- 3
- 1
- 2
Q. Which of the following statement is true about the equation x4+2x2−8x+3=0 ?
- There are 2 negative real roots
- There are 2 positive real roots, 2 imaginary roots
- There are 1 positive real root, 1 negative real root, 2 imaginary roots
- There are 4 imaginary roots
Q. If 4x6+ax3+5x−7=0 has a maximum of 4 possible real roots, then which of the following is true?
- None of the above
- a>0
- a<0
- a=0
Q. Which of the following statement is true about the equation x4+2x2−8x+3=0 ?
- There are 2 positive real roots, 2 imaginary roots
- There are 4 imaginary roots
- There are 2 negative real roots
- There are 1 positive real root, 1 negative real root, 2 imaginary roots
Q.
The number of positive real roots for polynomial equation f(x) is given by________.
Degree of the equation
No. of times sign is changing in f(-x)
Total number of positive terms in f(x)
No. of times sign is changing in f(x)
Q. Using Descartes Rule of Signs, the maximum possible no. of real roots for f(x)=x6+8x2−14x+1 is
Q. By Descarte's rule of sign, the maximum number of positive real roots of equation x5−6x4+7x3+8x2+9x+10=0
Q. The maximum possible number of real roots for f(x)=x3−8x2−9x+12 is:
- 0
- 1
- 2
- 3
Q. If for the cubic equation x3−4x2+x+6=0, the possible no. of positive real roots are 2 or 0 and the possible no. of negative real roots is 1, then which of the following can be true?
- Number of positive roots:2
Number of imaginary roots:0 - Number of positive roots:0
Number of imaginary roots:2 - Number of positive roots:0
Number of imaginary roots:3 - Number of positive roots:2
Number of imaginary roots:3
Q. If for the cubic equation x3−4x2+x+6=0, the possible no. of positive real roots are 2 or 0 and the possible no. of negative real roots is 1, then which of the following can be true?
- Number of positive roots:2
Number of imaginary roots:0 - Number of positive roots:2
Number of imaginary roots:3 - Number of positive roots:0
Number of imaginary roots:3 - Number of positive roots:0
Number of imaginary roots:2
Q. Using Descartes Rule of Signs, the maximum possible no. of real roots for f(x)=x3−8x2−9x+12 is:
- No. of negative real roots can be 2
- No. of positive real roots can be 2
- No. of real roots can be 3
- No. of positive real roots can be 1
Q. By Descartes rule of sign, the maximum number of negative real roots of equation x5−6x4+7x3+8x2+9x+10=0
Q. Using Descartes Rule of Signs, the maximum possible no. of real roots for f(x)=x3−8x2−9x+12 is:
- No. of positive real roots can be 2
- No. of real roots can be 3
- No. of positive real roots can be 1
- No. of negative real roots can be 2
Q. If 4x6+ax3+5x−7=0 has a maximum of 4 possible real roots, then which of the following is true?
- a>0
- None of the above
- a<0
- a=0
Q. Select the correct statements for the equation x5+4x4−3x2+x−6=0 ?
- The number of positive roots can be 3
- The number of positive roots can be 4
- The number of positive roots can be 1
- The number of positive roots can be 2
Q. The mximum number of real roots of the equation f(x)=x6+8x2−14x+1 is
- 6
- 2
- 1
- 0
Q. If 4x6+ax3+5x−7=0 has a maximum of 4 possible real roots, then which of the following is true?
- None of these
- a<0
- a=0
- a>0
Q. Select the correct statements for the equation x5+4x4−3x2+x−6=0.
- The number of negative roots can be 1
- The number of negative roots can be 3
- The number of negative roots can be 0
- The number of negative roots can be 2
Q. If for the cubic equation x3−4x2+x+6=0, the possible no. of positive real roots are 2 or 0 and the possible no. of negative real roots is 1, then which of the following can be true?
- Number of positive roots:0
Number of imaginary roots:2 - Number of positive roots:2
Number of imaginary roots:0 - Number of positive roots:0
Number of imaginary roots:3 - Number of positive roots:2
Number of imaginary roots:3
Q. Let f(x) be a polynomial of degree 3 such that f(k)=−2k for k=2, 3, 4, 5. Then the value of 52−10f(10) is equal to
Q. The maximum possible number of real roots of the equation x5−6x2−4x+5=0 is
Q.
Determine the number of positive real roots and imaginary roots for equation 3 x7 + 2 x5 + 4 x3 + 11x - 12 = 0.
4, 3
2, 5
3, 4
1, 6