Equation of Plane Containing Two Lines
Trending Questions
- x+2y−2z=0
- 3x+2y−3z=0
- x−2y+z=0
- 5x+2y−4z=0
The equation of straight line equally inclined to the axes and equidistant from the points and is where:
None of these
- x−z=0
- 2y+2z=1
- x+4y+3z=0
- x+2y+z=0
x+23=y−25=z+57 and x−11=y−44=z+47 , is:
- 11√6
- 6√11
- 11
- 11√6
- coordinates of B are (−7, 0, 19)
- equation of reflected ray is x−52=y−61=z−7−2
- equation of plane containing the incident ray and the reflected ray is 3x−4y+z+2=0
- equation of incident ray is x−16=y−2−2=z−316
- 3
- √3
- 13
- 1√3
If the planes , and pass through a straight line, then is
The point of intersection of lines represented by the equation is
None of these
- Equation of the incident ray is x+y−13=0
- Equation of the incident ray is 3x−y+1=0
- Equation of the reflected ray is x−2y−3=0
- Equation of the reflected ray is x+3y−13=0
- (2, 5, 7)
- (1, 11, 3)
- (0, 0, 0)
- (0, 2, 3)
- 63√5
- 17√5
- 11√5
- 205√5
Equation of the plane containing the straight line x2=y3=z4 and perpendicular to the plane containing the staight lines x3=y4=z2 and x4=y2=z3 is
5x + 2y - 4z = 0
x +2y - 2z = 0
3x + 2y - 2z = 0
x - 2y + z =0
Find the equation of the plane through the points (2, 1, -1), (-1, 3, 4) and perpendicular to the plane x-2y+4z=10.
- x−2y+3z−14=0
- x−2y+z+9=0
- x+2y−3z+5=0
- x+2y−3z−14=0
- 3x−2y+4z−2=0
- 2x+3y+z+4=0
- 2x−4y−3z+6=0
- x+2y+z+4=0
- Any positive value of a, b, and c other than 1
- Any positive values of a, b, and c where either a≠b, b≠c or a≠c
- Any three distinct positive values of a, b, and c
- There exist no such positive real numbers a, b, and c
- 23
- 13
- √23
- 2√3
- 2x+y+2=0
- 3x+y−z=2
- 2x−3y+8z=3
- none of these
A plane parallel to axis passing through line of intersection of planes and which of the point lie on the plane
- √612
- √14
- √602
- 4
x−αl=y−βm=z−γn and x−α′l′=y−β′m′=z−γ′n′
lie in the same plane then the equation of the plane is -
- ∣∣ ∣∣xyzlmnl′m′n′∣∣ ∣∣=0
- ∣∣ ∣∣x−αy−βz−γlmnl′m′n′∣∣ ∣∣=0
- ∣∣ ∣∣l−l′m−m′n−n′lmnl′m′n′∣∣ ∣∣=0
- None of these
- 5x−8y−4z=0
- 5x+8y−4z=0
- 5x−8y+4z=0
- 5x+8y+4z=0
Find the shortest distance between the lines whose vector equtions are
r=(1−t)^i+(t−2)^j+(2−2t)^k and r=(s+1)^i+(2s−1)^j−(2s+1)^k
The value of k so that the lines 2x – 3y + k = 0, 3x – 4y – 13 = 0 and 8x – 11y – 33 = 0 are concurrent, is
-7
5
-5
7
- √135
- √135
- √175
- √175