Slope Intercept Form of a Line

Q. Find the equation of the straight line that has y - intercept 5 and is parallel to the straight line x - 3y = 3

1. x - y +5=0

2. 2x - 3y +12 = 0

3. x - 3y + 15 =0

4. 3x - y + 5 = 0

Q.

The equation of the straight line which makes an angle of ${15}^{\circ }$ with the positive direction of x-axis and cuts an intercept of length 4 on the negative direction of y-axis, is

1. 

2. 

3. 

4. 

Q. The equation of the line whose slope is 3 and which cuts off an intercept 3 from the positive x - axis is

1. y=3x+9
2. None of these
3. y=3x-9
4. y=3x+3

Q.

A line cuts the x - axis at A(7, 0) and the y - axis at B(0, -5). A variable line PQ is drawn perpendicular to AB. Cutting the x - axis at P and the y - axis at Q.
If AQ and BP intersect at R, the locus of R is

1. 5x - 7y = 35

2. $x^2+y^2-7x+5y=0$

3. $x^2+y^2+7x-5y=0$

4. none of these

Q. The number of integral values of m, for which the x-coordinate of the point of intersection of the lines $3x+4y=9$ and $y=mx+1$ is also an integer, is

1. 4
2. 2
3. 0
4. 1

Q. The equation of the line cutting off an intercept of 3 on the Y-axis and parallel to the line joining points A(4, -5) and B(1, 2) is .

1. 3x+7y-9 = 0
2. 3x-7y+9 = 0
3. 3y-7x+9 = 0
4. 3y+7x-9 = 0

Q. Equation of line(s) passing through (0, -2) which is/are equally inclined to the coordinate axes will be

1. y = x-2
2. y = -x+2
3. y = x-1
4. y = -x-2

Q. The equation of the line which makes an angle of ${15}^{\circ }$ with positive $x$-axis and cuts-off an intercept of $3$ unit on the negative $y$-axis is

1. $y-(2-\sqrt{3})-3=0$
2. $y-(2+\sqrt{3})x+3=0$
3. $y+(2-\sqrt{3})x+3=0$
4. $y-(2-\sqrt{3})x+3=0$

Q. The slope intercept form of the line $\frac{x}{2}+\frac{y}{4}=1$ is

1. $y=-2x+4$
2. $y=2x+4$
3. $y=4x+2$
4. $y=-4x+2$

Q. The equation of the line parallel to the line joining $(4,2)$ and $(2,4)$ and whose $y$-intercept is $4$ units along positive $y$- axis is

1. $y+x+4=0$
2. $x-y+4=0$
3. $2x+y=0$
4. $y+x-4=0$