Alpha Decay
Trending Questions
The number of α and β particles emitted in the above conversion is
- 3α, 5β
- 5α, 6β
- α, 3β
- 2α, 4β
- Zinc sulphide screen
- Barium sulphate
- Thin aluminum sheet
Gold foil
256103Lr→abMd+α
Where α represents the alpha particle given out. What are the values of a and b?
- a=252 ; b =105
- a=260 ; b =101
- a=260 ; b =105
- a=252 ; b =101
- 22789X
- 21583X
- 21575X
- None of these
Th234 disintegrates and emits 6β- and 7α-particles to form a stable element. Find the atomic number and mass number of the stable product. Also identify the element.
(IIT-JEE, 2004)
- 82Pb206.
- 80Pb204.
- 82Pb204.
- 80Hg202.
Calculate the number of α- and β-particles emitted when 92U238 changes into radioactive 82Pb206.
(IIT-JEE, 2000)
- 3, 4
- 4, 3
- 6, 8
- 8, 6
Calculate the total number of α- and β-particles emitted in the nuclear reaction 92U238⟶82Pb214.
(IIT-JEE, 2009)
- 4
- 6
- 8
- 9
Thorium with atomic number 92 and mass number 238 disintegrates to give Pb with atomic number 82 and mass number 206. How many alpha and beta particles are emitted during this process?
7 and 8
6 and 7
7 and 6
9 and 6