Definition of a Projectile
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Q.
The figure shows two positions A and B at the same height h above the ground. If the maximum height of the projectile is H, then determine the time t elapsed between the positions A and B in terms of H.
√4g(H−h)
√2g(H−h)
√8g(H−h)
√6g(H−h)
Q.
The initial velocity of a projectile of mass 1 kg is given by u=(^i+√3 ^j) m/s. What is the time of flight?
2√35 s
√310 s
3√35 s
√35 s
Q. A missile was thrown from the top of the Himalayas to Kanyakumari. In absence of air resistance, this motion can be best categorized as .
- 1D motion
- 2D motion
- 3D motion
Q. 
A particle is projected from ground as shown. It is at point A at time t1, at point B at time t2, at point C at time t3 & at time t4 it is at D then

A particle is projected from ground as shown. It is at point A at time t1, at point B at time t2, at point C at time t3 & at time t4 it is at D then
- −→VB−−→VA=−→VD−−→VC
- −→VAt1=−→VBt2=−→VCt3=−→VDt4
- −→VB−−→VAt2−t1=−→VD−−→VCt4−t3
- −→VA+−→VB2=−→VC+−→VD2
Q. A particle is projected with initial velocity →v=3^i+4^j+12^k & →a = 8^i+6^j−4^k then path of particle is
- parabolic
- not defined as vector in 3D
- curved but not parabolic
- straight line
Q. In the given figure for a projectile


- y=[x1x2x1−x2]tanθ
- y=[x1x2x1+x2]tanθ
- y=[2x1x2x1+x2]cosθ
- y=[2x1x2x1+x2]tanθ
Q. If the time of flight of a projectile is doubled, what happens to the maximum height attained?
- Doubled
- Halved
- Remains unchanged
- Becomes four times
Q. Assertion :The projectile has only vertical component of velocity at the highest point of its trajectory. Reason: At the highest point only one component of velocity is present.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. A projectile is fired from the top of a 40m hight cliff with an initial speed of 50m/s at an unknown angle. Find its speed when it hits the ground.
Q. An object is projected from ground with speed 20 m/s at angle 30o with horizontal. Its centripetal acceleration one second after the projection is [Take g=10 m/s2]
- 10 m/s2
- zero
- 5 m/s2
- 12 m/s2