The distance of the closest approach of an alpha-particle fired towards a nucleus with momentum is If the momentum of the alpha-particle is , the corresponding distance of the closest approach is
A particle of mass is moving along the x-axis with an initial velocity . It collides elastically with a particle of mass at rest and then moves with half its initial kinetic energy (see figure). If then value of is
Q. Statement -1: Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement -2 : Principle of conservation of momentum holds true for all kinds of collisions.
Statement -1 is ture , statement -2 is true, and statement-2 is correct explanation of statement -1.
Statement-1 is ture, statement-2 is true, but statement -2 is not a correct explanation of statement-1.
Q. State TRUE or FALSE for given STATEMENTS , Give REASON for FALSE statement : (i) Total mechanical energy is always conserved in collision . (ii) Kinetic energy is always conserved in collisions . (iii) Velocity before and after collision of respective bodies remain same . (iv) Total momentum is always conserved in collisions .
Q. Two ice skaters A and B approach each other at right angles. Skater A has a mass 30 kg and velocity 1 m/s skater B has a mass 20 kg and velocity 2 m/s. They meet and cling together. The final velocity of the couple is
Q. A bullet of mass 20 g and moving with 600 m/s collides with a block of mass 4 kg hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision? (Take g=10m/s2)