Pressure vs Velocity
Pressure is exerted by a gas on the walls of the container because
It loses kinetic energy
It sticks with the walls
On collision with the walls there is a change in momentum
It is accelerated towards the walls
- Common man, I don't wanna do this.
Assume that the temperature remains essentially constant in the upper part of the atmosphere. Obtain an expression for the variation in pressure with height in the upper atmosphere. The mean molecular weight of air is M. Assume a variable PO for the pressure at a height h = 0, where h = 0 depends on the choice of origin (could very well be at the beginning of the stratosphere, for example).
He attached a small U-tube at the end of a Toricellian tube and powered in mercury from the open end (T); as mercury rose in the closed, shorter column, the trapped air would get more and move compressed - which could only mean, that the pressure increased, and the volume decreased (these were respectively measured by the height of the mercury column, h, and a scale on the shorter column, V, for volume of the trapped air).
Which of these statements is/are correct in regard to Boyle's conclusion from the data?
The height difference of the two levels is directly proportional to the pressure of the trapped air
As the value of h increased, V monotonically decreased
If we blow air through the open end of T, then h would be a bad measure for the pressure of the trapped air
The graph of h versus the reciprocal of V is a straight line
The Bat Life: To monitor the pressure of helium in the canister, Batman had placed 2 sensors which sense pressure and temperature at points P1 and P2. When the piston was in motion, Batman's suit registered an error in the canister. When he analysed the error back in the Batcave he noticed that the pressure at points P1 and P2 were different. Which amongst the following statements is true?
- its a trick of the JOKER.
- none of the above
The sensors which detect the pressure at points P1 and P2 are faulty. A gas confined within a single boundary cannot have twovalues of pressure
The sensors need not necessarily be faulty, as the gas is not in equilibrium.
An air bubble of radius 2.0 mm is formed at the bottom of a 3.3 m deep river. Calculate the radius of the bubble as it comes to the surface. Atmospheric pressure =1.0×105 Pa and density of water =1000 kg m−3
Two containers of equal volume contain the same gas at pressures P1 and P2 and absolute temperatures T1 and T2 respectively. On joining the vessels, the gas reaches a common pressure P and common temperature T. The ratio PT is equal to