Millikan's Oil Drop Experiment

Q. An oil drop has 7.99 $\times$ ${10}^{-19}$ C charge. The number of electrons that the oil drop has is .

1. 2
2. 5
3. 3

Q.

Assume that Millikan performed the oil drop experiment. In the oil drop experiment, the following charges(in arbitrary units) were found on a series of oil droplets.

The data obtained is as follows:

2 $\times$ ${10}^{-19}$ C
4 $\times$ ${10}^{-19}$ C
6 $\times$ ${10}^{-19}$ C

Calculate the magnitude of the charge on the electron.

1. 1.6 $\times$ ${10}^{-19}$ C

2. 4 $\times$ ${10}^{-15}$ C

3. 2 $\times$ ${10}^{-19}$ C

4. 2 $\times$ ${10}^{-15}$ C

Q.

The charge on the electron is-

1. - 1.7 × 10^-11C

2. None of these

3. - 1.6 × 10^-19C

4. - 9.1 × 10^-31C

Q.

If $\frac{e}{m_e}$ = 1.758820 $\times$ ${10}^{11}$ C ${kg}^{-1}$

The mass of an electron is

1. 9.1094 × 10^-31

2. 6.1094 × 10^-31

3. 6.1094 × 10^-21

4. 9.1094 × 10^-21

Q.

The charge on the electron was found out by

1. Rutherford

2. R.A Millikan

3. J.J. Thomson

4. Chadwik

Q.

An oil drop has 7.99 $\times$ ${10}^{-19}$ C charge. How many electrons does this oil drop has?

1. 2

2. 3

3. 4

4. 5

Q. The increasing order of the values of e/m (charge/ mass) is :

1. n, α, p, e
2. e, p, n, α
3. n, p, α, e
4. n, p, e, α

Q. In Millikan’s oil drop experiment, the forces acting on a moving drop of oil are:

1. Gravitational force and viscous drag
2. Electrostatic force and acceleration force
3. None of the above
4. Gravitational force, electrostatic force and viscous drag

Q. In Millikan’s oil drop experiment, the oil drop stops if:

1. Electrostatic force = viscous force
2. Magnetic force = viscous force
3. Electrostatic force = magnetic force
4. Electrostatic force = gravitational force

Q. Millikan’s oil drop experiment was conducted to measure the value of the:

1. e/m ratio
2. Charge ‘e’ on an electron
3. Mass of a proton
4. Mass of an electron