Potassium Dichromate
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Q. Potassium peroxochromate K3CrO8 is a red-brown paramagnetic solid prepared from the following reaction.
CrO2−4+H2O2+OH−→[CrO8]3−+H2O+O2
If oxidation state of Cr in product is X, number of peroxide bonded O in product is Y and number of electrons in d orbital of Cr is Z then what is value of X+Y+Z?
CrO2−4+H2O2+OH−→[CrO8]3−+H2O+O2
If oxidation state of Cr in product is X, number of peroxide bonded O in product is Y and number of electrons in d orbital of Cr is Z then what is value of X+Y+Z?
Q.
X+H+⟶Y+Na++H2O
Y+KCl⟶K2Cr2O7+NaCl
Find X and Y.
X=Na2Cr2O7;Y=Na2CrO4
X=Na2Cr2O7;Y=Na2Cr2O7
X=Na2CrO4;Y=Na2Cr2O7
X=Na2Cr2O4;Y=Na2CrO4
Q. Which of the statements is not true?
- K2Cr2O7 solution in acidic medium is orange
- Na2Cr2O7 is preferred over K2Cr2O7 in volumetric analysis
- K2Cr2O7 solution becomes yellow on increasing the pH beyond 7
- On passing H2S through acidified K2Cr2O7 solution, a milky colour is observed
Q.
FeCr2O4+Na2CO3+O2⟶X+Y+CO2
Mention X and Y.
X=Na2CrO4;Y=Fe2O3
X=Na2Cr2O7;Y=Fe3O3
X=Na2Cr2O7;Y=Fe3O4
X=Na2Cr2O4;Y=Fe3O4
Q. When potassium dichromate is heated with conc.H2SO4 and NaCl, orange vapours are evolved due to
- CrO2Cl2
- CrCl3
- Cl2
- CrO5
Q. When potassium dichromate crystals are heated with conc. H2SO4, we get
- Hydrogen
- oxygen
- Sulphur Dioxide
- Hydrogen sulphide
Q. When K2Cr2O7 is heated with conc. H2SO4 in the presence of a soluble metal chloride, orange red vapours are produced. These are due to
- CrCl3
- CrOCl2
- CrO2Cl2
- CrO2−4
Q. In Cr2O2−7
- 4Cr-O bonds are equivalent
- 6 Cr-O bonds are equivalent
- All Cr-O bonds are equivalent
- All Cr-O bonds are non-equivalent
Q. Ammonium dichromate is used in some fireworks. The green-coloured powder blown in the air is (IIT JEE, 1997)
- CrO(O2)
- CrO3
- Cr2O3
- Cr
Q. The equilibrium :
Cr2O2−7 →← 2CrO2−4 exists in
Cr2O2−7 →← 2CrO2−4 exists in
- Acidic Medium
- Basic Medium
- Neutral Medium
- Does not exist