Potassium Permanganate
Trending Questions
Q. The product of oxidation of I− ion by MnO−4 in alkaline medium is
- I2
- IO−3
- I−3
- IO−4
Q. On addition of small amount of KMnO4 to concentrated H2SO4, a green oily compound is obtained which is highly explosive in nature. Identify the compound from the following.
- MnO2
- MnSO4
- Mn2O3
- Mn2O7
Q. Why is HCl not used to make the medium acidic in oxidation reactions of KMnO4 in acidic medium?
- KMnO4 acts as a reducing agent in the presence of HCl
- KMnO4 is a weaker oxidising agent than HCl
- KMnO4 oxidises HCl into Cl2 which is also an oxidising agent
- Both HCl and KMnO4 act as oxidising agents
Q. When KMnO4 solution is added to oxalic acid solution, the decolourisation is slow in the beginning but becomes instantaneous after some time because:
- CO2 is formed as the product
- MnO−4 catalyses the reaction
- Mn2+ acts as an autocatalyst
- The reaction is exothermic
Q. Reduction of the metal centre in aqueous permanganate ion involves
- 3 electrons in neutral medium
- 5 electrons in neutral medium
- 3 electrons in alkaline medium
- 5 electrons in acidic medium
Q. The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is
- 1
- 2
- 5
- 15
Q. In neutral medium, KMnO4 acts as a powerful oxidizing agent according to the reaction:
2KMnO4+H2O→2MnO2+2KOH+3(O). The change involves
2KMnO4+H2O→2MnO2+2KOH+3(O). The change involves
- Loss of 3e−
- Increase of 3e−
- Loss of 5e−
- Gain of 5e−
Q. When MnO2 is fused with KOH, a coloured compound is formed. The product and its colour is
- Mn2O3, brown
- K2MnO4, green
- KMnO4, purple
- Mn2O4, black
Q. In a redox reaction, how many moles of electrons are accepted by 1 mole of MnO4 in acidic medium?
- 3
- 5
- 6
- 52
Q. In acidic medium if potassium permanganate is used as an oxidizing agent, we get
- MnO2−4
- Mn2+
- MnO2
- Mn2O3