Synthesis Using Azide & Gabriel Synthesis

Q.

In this sequence, incorrect statement is

1. 'A' is phthalimide
2. C is methyl phathalimide
3. Formation of 'D' and 'E' from 'A' is Hoffmann bromamide reaction
4. Among the final products one of the product is 1⁰amine

Q. Gabriel phthalimide synthesis can be used for the synthesis of aromatic primary amines.

1. True
2. False

Q.

Which of the following method is used to prepare pure aliphatic primary amine

1. Gattermann - Koch reaction

2. GabrielPhthalimide synthesis

3. Hoffmann degradation method

4. Carbylamine reaction

Q. Treatment of compound O with $KMn{O}_4/H^{+}$ gave P, which on heating with ammonia gave Q. The compound Q on treatment with $B{r}_2/NaOH$ produced R. On strong heating, Q gave S, which on further treatment with ethyl 2-bromopropanoate in the presence of $KOH$ followed by acidification, gave a compound T.

The compound R is:

1. 
2. 
3. 
4. 

Q. Which of the following are useful to synthesize ethylamine?

1. Potassium salt of phthalimide on reaction with ethylbromide followed by hydrolysis.
2. Reduction of acetamide or azidoethane using $LiAl{H}_4$ followed by work up
3. Reductive amination of acetaldehyde with $N{H}_3$ using $NaB{H}_{3}CN$
4. Reductive amination of acetaldehyde with $N{H}_3$ using catalytic reduction

Q. Method by which Aniline cannot be prepared is:

1. reduction of nitrobenzene with $H_2/Pd$ in ethanol
2. potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous $NaOH$ solution
3. hydrolysis of phenylisocyanide with acidic solution
4. degradation of benzamide with bromine in alkaline solution

Q. The best method for preparing primary amines from alkyl halides without changing the number of carbon atoms in the chain is:

1. Hoffmann Bromamide reaction
2. Gabriel phthalimide synthesis
3. Sandmeyer reaction
4. Reaction with $N{H}_3$

Q.

Which of the following amines cannot be prepared by Gabriel Synthesis?

1. Butyl amine

2. Isopropyl amine

3. 2-phenylethyl amine

4. N -methyl benzyl amine.