Director Circle: Hyperbola
Trending Questions
Q.
For a standard hyperbola
x2a2−y2b2=1
Match the following.
Column 1Column 21.a2>b2P.Director circle is real2.a2=b2Q.Director circle is imaginary3.a2<b2R.Centre is the only point from which two perpendicular tangents can be drawn on thehyperbola
1−P, 2−Q, 3−R
1−R, 2−Q, 3−P
1−P, 2−R, 3−Q
1−Q, 2−P, 3−R
Q. Which among the following option(s) is/are correct for hyperbola x2a2−y2b2=1, where n is the number of points on the plane through which perpendicular tangents are drawn to it and e is the eccentricity.
- If n=1, then e=√2
- If n>1, then 0<e<√2
- If n=0, then e>√2
- If n=0, then e>2
Q.
Find the equation to the director circle of the hyperbola x2a2−y2b2=1
x2+y2=a2−b2
x2−y2=a2−b2
x2+y2=a2+b2
x2−y2=a2+b2
Q.
Find the equation to the director circle of the hyperbola x2a2−y2b2=1
x2+y2=a2−b2
x2−y2=a2−b2
x2+y2=a2+b2
x2−y2=a2+b2
Q. The perpendicular tangents drawn to the hyperbola
x225−y216=1
intersect on the curve x2+y2=9
x225−y216=1
intersect on the curve x2+y2=9
- False
- True
Q. The perpendicular tangents drawn to the hyperbola
x225−y216=1
intersect on the curve x2+y2=9
x225−y216=1
intersect on the curve x2+y2=9
- False
- True