Distance Formula
Trending Questions
Q. Consider a parabola y=x24 and the point F(0, 1). Let A1(x1, y1), A2(x2, y2), A3(x3, y3), ..., Ak(xk, yk) are 'n' points on parabola such as xk>0 and ∠OFAk=kπ2n, (k=1, 2, 3, ..., n). Then the value of limn→∞1nn∑k=1FAk is
- 2π
- 4π
- 8π
- 16π
Q. The shortest distance between the point (32, 0) and the curve y=√x, (x>0), is :
- √52
- 32
- 54
- √32
Q. The length of the latus rectum of a conic is 5. Its focus is (−1, 1) and its directrix is 3x−4y+2=0, then the conic is
- a parabola
- an ellipse
- a hyperbola
- a circle
Q.
Find the locus of the point P if AP2−BP2=18, where A ≡ (1, 2, –3) and B ≡ (3, –2, 1)
2x + 3y + 4 = 9
2x – 4y + 4z = 9
2x + 4y + 4z = 9
2x – 3y + 4z = 9
Q.
___
What is the distance between the point A(0, 7, 10) and C(–4, 9, 6) in space?
Q. A point P in space is such that the sum of square of its distances from x−axis, y−axis and z−axis is 9 units more than the sum of square of its distances from xy−plane, yz−plane and zx−plane. Then the distance( in units) of point P from origin is equal to
Q. The point equidistant from the points (a, 0, 0), (0, b, 0), (0, 0, c) and (0, 0, 0) is
- (a3, b3, c3)
- (a, b, c)
- (a2, b2, c2)
- (4a, 4b, 4c)
Q. Points (1, 1, 1), (–2, 4, 1), (–1, 5, 5) and (2, 2, 5) are the vertices of a
- Parallelogram
- Trapezium
- Rectangle
- Square
Q.
Find the locus of the point P if AP2−BP2=18, where A ≡ (1, 2, –3) and B ≡ (3, –2, 1)
2x + 3y + 4 = 9
2x – 4y + 4z = 9
2x + 4y + 4z = 9
2x – 3y + 4z = 9
Q.
The length of perpendicular drawn from the point (5, 4, -1) to the line →r=^i+λ(2^i+9^j+5^k) is
none of these
√2001112
√2309112
√2109110