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Question

A 1 kg stationary bomb is exploded in three parts having mass ratio 1:1:3. Parts having same mass move in perpendicular directions with velocity 30 m/s, then the velocity of bigger part will be:

A
102 m/s
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B
102 m/s
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C
152 m/s
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D
152 m/s
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Solution

The correct option is A 102 m/s
Two parts having same masses move in perpendicular directions. So, the resultant is the third one having mass 3 times of the two masses.
So, the resultant is =(30)2+(30)2=1800=302
Since, the bigger part is thrice in mass of the other two parts.
So, 3023=102 ms1
The velocity of bigger part is 102 ms1

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