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Question

A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at constant speed of 4 m/sec. The tension in the string is 6 N, when the stone is at (g = 10 m/sec2)
 


  1. None of the above

  2. Bottom of the circle

  3. Top of the circle

  4. Half way down


Solution

The correct option is C

Top of the circle


mg = 1×10 = 10N, mv2r = 1×(42)1 = 16
Tension at the top of circle = mv2r - mg = 6N
Tension at the bottom of circle = mv2r+mg = 26N

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