CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 m/s. The tension in the string is 6 N, when the stone is
(Take g=10 m/s2)
  1. At the top of the circle 
  2. At the bottom of the circle 
  3. None of above
  4. Half way down 


Solution

The correct option is A At the top of the circle 
Let the position of the stone at an instance as shown in figure.


Centrifugal force acting on the stone,
mv2R=1×421=16 N
Weight of the stone, mg=1×10=10 N
Balancing the forces acting on the stone, 
T=mg cos θ+mv2R
6=10cos θ+16
cos θ=1
θ=180
At this angle, the stone will be at the top of the circle.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...



footer-image