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Question

# A 1 kg stone at the end of 1 m long string is whirled in a vertical circle at a constant speed of 4 m/s. The tension in the string is 6 N, when the stone is (Take g=10 m/s2)

A
At the top of the circle
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B
At the bottom of the circle
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C
Half way down
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D
None of above
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Solution

## The correct option is A At the top of the circle Let the position of the stone at an instance as shown in figure. Centrifugal force acting on the stone, mv2R=1×421=16 N Weight of the stone, mg=1×10=10 N Balancing the forces acting on the stone, ⇒T=mg cos θ+mv2R 6=10cos θ+16 cos θ=−1 θ=180∘ At this angle, the stone will be at the top of the circle.

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