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Question

A 10.0g a sample of a mixture of calcium chloride and sodium chloride is treated with Na2CO3 to precipitate the calcium as calcium carbonate. This CaCO3 is heated to convert all the calcium to CaO and the final mass of CaO is 1.62gms. The % by mass of CaCl2 in the original mixture is :

A
15.2%
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B
32.1%
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C
21.8%
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D
11.07%
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Solution

The correct option is C 32.1%
CaCO3+heatCaO+CO2
X 1.68gm
[molecular mass of CaCO3=100u
molecular mass of CaO=56u
cross multiply through the equation and solve for x grams of CaCO3
x=1.62×10056
x=2.89gm
CaCl2+Na2CO3CaCO3+2NaCl
Again cross multiply through the equation and solve for x grams of CaCl2
x=2.89

x=2.89×111100
x=3.2gm
%CaCl2 in original mixture 3.2grams
CaCl2 over 10gms mixture is 32%

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