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Question

# A 10.0g a sample of a mixture of calcium chloride and sodium chloride is treated with Na2CO3 to precipitate the calcium as calcium carbonate. This CaCO3 is heated to convert all the calcium to CaO and the final mass of CaO is 1.62gms. The % by mass of CaCl2 in the original mixture is :

A
15.2%
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B
32.1%
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C
21.8%
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D
11.07%
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Solution

## The correct option is C 32.1%CaCO3+heat⟶CaO+CO2X 1.68gm[molecular mass of CaCO3=100umolecular mass of CaO=56ucross multiply through the equation and solve for x grams of CaCO3x=1.62×10056x=2.89gmCaCl2+Na2CO3⟶CaCO3+2NaClAgain cross multiply through the equation and solve for x grams of CaCl2x=2.89x=2.89×111100x=3.2gm%CaCl2 in original mixture 3.2grams CaCl2 over 10gms mixture is 32%

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