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Question

A $$10$$ kg mass is resting on a horizontal surface and horizontal force of $$80$$ N is applied. If $$\mu =0.2$$, the ratio of acceleration without friction and with friction is ($$g = 10ms^{-2}$$)


A
34
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B
43
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C
12
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D
2
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Solution

The correct option is B $$\dfrac{4}{3}$$
$$\displaystyle \frac{a_{1}}{a_{2}}= \displaystyle \frac{\displaystyle \frac{F}{m}}{\displaystyle \frac{F-\mu mg}{m}}$$
$$a_1 = \displaystyle \frac{F}{m} = \frac{80}{10} = 8\ m/s^2$$
$$a_2 = \displaystyle \frac{F-\mu  mg}{m} = \frac{80 - 0.2\times 10\times 10}{10} = 6\ m/s^2$$
$$\therefore \displaystyle \frac{a_{1}}{a_{2}}= \frac{8}{6}= \frac{4}{3}$$

Physics

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