Question

# A $$10$$ kg mass is resting on a horizontal surface and horizontal force of $$80$$ N is applied. If $$\mu =0.2$$, the ratio of acceleration without friction and with friction is ($$g = 10ms^{-2}$$)

A
34
B
43
C
12
D
2

Solution

## The correct option is B $$\dfrac{4}{3}$$$$\displaystyle \frac{a_{1}}{a_{2}}= \displaystyle \frac{\displaystyle \frac{F}{m}}{\displaystyle \frac{F-\mu mg}{m}}$$$$a_1 = \displaystyle \frac{F}{m} = \frac{80}{10} = 8\ m/s^2$$$$a_2 = \displaystyle \frac{F-\mu mg}{m} = \frac{80 - 0.2\times 10\times 10}{10} = 6\ m/s^2$$$$\therefore \displaystyle \frac{a_{1}}{a_{2}}= \frac{8}{6}= \frac{4}{3}$$Physics

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