A 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is:
In the complete neutralization of acid and base, the Milli-equivalent of acid and base must be equivalent.
Milli-equivalent of HCl =
Milli-equivalent of NaOH =
Let the titration be completed by adding a ‘V3’ volume of 0.25 N KOH solution.
The titration is completed by adding a ‘16ml’ volume of 0.25 N KOH solution.
Hence, option (d) is correct.