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Center of Mass as an Average Point

A 15 kg mass,...

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A 15 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 4T radian/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm². The elongation of the wire when the mass is at the lowest point is (g = 10 m/s²)

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A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm². Calculate the elongation of the wire when the mass is at the lowest point of its path.

Q. A 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065

c m^{2}

. Calculate the elongation of the wire when the mass is at the lowest point of its path.

Q. 14.5 kg mass, fastened to the end of a steel wire of unstretched length 1.0 m, is whirled in a vertical circle with an angular velocity of 2 rev/s at the bottom of the circle. The cross-sectional area of the wire is 0.065 cm2. Calculate the elongation of the wire when the mass is at the lowest point of its path

15 k g

mass fastened to the end of a steel wire of unstretched length

1.0 m

is whirled in a vertical circle with an angular velocity of

2 r e v

s^{- 1}

at the bottom of the circle. The cross-section of the wire is

0.05 {c m}^{2}

. The elongation of the wire when the mass is at the lowest point of its path is
(Take

g = 10 m s^{- 2}, Y_{s t e e l} = 2 \times 10^{11} N m^{- 2}

)

6

-kg weight is fastened to the end of a steel wire of un-stretched length

60

cm. It is whirled in a vertical circle and has an angular velocity of

2

revolution per second at the bottom of the circle. The area of cross-section of the wire is

0.05 c m^{2}

. Calculate the elongation of the wire when the weight is at the lowest point of the path. Young's modulus of steel

= 2 \times 10^{11}

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