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Question

A 20 -kg block is placed on a top of a 50-kg block as shown in fig., A (50 kg) horizontal force F acting on A causes an acceleration of 3ms−2 to A and 2ms−2 to B(20 kg) as shown in the figure. For this situation, mark out the correct statement(s)

988170_0bdd3a6240a640a89a609a189a66cd3c.png

A
The friction force between A and B is 40 N.
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B
The net force acting on A is 150 N.
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C
The value of F is 190 N.
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D
The value of F is 150 N.
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Solution

The correct options are
A The friction force between A and B is 40 N.
B The net force acting on A is 150 N.
C
The value of F is 190 N.

Let f be the friction force on both the block A and B as shown in the FBD diagram.
A block has an acceleration of 3ms2
Ff=50×3 eq(1)..
B block has an acceleration of 2ms2
f=20×2 eq(2)...
on solving eq(1) and eq(2).
f=40N
F=190N
the total force acting on the A block is
Ff=19040=150N.
Hence A,B and C is correct option.

959937_988170_ans_8cadfc588ecc4a4ba33227c0798400d7.png

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