A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
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Solution
θ=90o
For magnetic force
F=BIlsinθ=8.1×10−2N
Direction of force can be obtained from Fleming's left hand rule.