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Question


  1. A (3, 2),    B(–2,  1), C (0,  3), 2x + 2y – 4 = 0

  2. A (2, 3),    B(–1,  2), C (3,  0), 2x + y – 2  = 0

  3. A (0, 3),    B(–1,  2), C (-3,  0), x + 2y – 8 = 0

  4. A (2, 3),    B(–1,  2), C (3,  0), x + 2y – 8 = 0


Solution

The correct option is D

A (2, 3),    B(–1,  2), C (3,  0), x + 2y – 8 = 0


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