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Question

# A 3 m wide rectangular channel carries a flow of 6 m3/s. The depth of flow at a section P is 0.5 m. A flat-topped hump is to be placed at the downstream of the section P. Assume negligible energy loss between section P and hump, and consider g as 9.81 m/s2. The maximum height of the hump (expressed in m) which will not change the depth of flow at section P is

A
0.20 m
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B
0.40 m
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C
0.23 m
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D
0.30 m
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Solution

## The correct option is A 0.20 mThe maximum hump (ΔZ) that can be provided is given by y+Q22gA2=ΔZhump+32yc Here, A=3×0.5=1.5 m2 yc=(Q2gB2)1/3=(629.81×32)1/3 =0.7415 m ⇒0.5+622×9.81×1.52=ΔZhump+32×0.7415 ⇒ ΔZhump=0.20 m

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