A 3 $Ω$ resistor and a 6 $Ω$ resistor are connected in parallel and the combination is connected in series to a battery of 5V and a 3 $Ω$ resistor. The potential difference across the 6 $Ω$ resistor

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Solution

The correct option is C 2V
According to the question the equivalent resistance of 3 ohm and 6 ohm resistance which kept in parallel is 2 ohm. So the current flow through the circuit is $I = 5 / (3 + 2) = 1 A$ . So the potential difference across the 6 $Ω$ resistor should be $V = 2 \times 1 = 2 V$ .

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