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Question

# A 30 kg block rests on a rough horizontal surface. A force of 200 N is applied on the block. The block acquires a speed of 4 m/s , starting from rest in 2 s . What is the value of coefficient of friction?

A
10/3
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B
3/10
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C
0.47
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D
0.185
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Solution

## The correct option is B 0.47The acceleration is given as v=u+at a=2m/s2 The force applied on the horizontal surface is such that it just overcome the static friction F−μN=ma 200−μ⋅30⋅10=30×2 The static friction is0.47

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