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Question

A 300 g mass has a velocity of (3^i+4^j)m/s at a certain instant. What is its kinetic energy


  1. 2.4 J

  2. 3.75 J

  3. 1.35 J

  4. 7.35 J


Solution

The correct option is B

3.75 J


v=(3^i+4^j)speed=v=32+42=5m/s. So kinetic energy = 12mv2=12×0.3×(5)2=3.75J

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