Question

# A 32-digit number has all 9’s. Find the remainder when the number is divided by 111.

A
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
99
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is D 99option d Any number of the form aaa (3 digits) or aaaaaa (multiple of 3 digits, i.e. 6, 9 .....) is divisible by 111 Therefore group the above numbers into groups of 3 or multiples of 3. A 32 digit number can be broken up as (3*10 digits) + (2 digits). The first part is divisible by 111. the last two digits will thus be the remainder = 99

Suggest Corrections
0
Join BYJU'S Learning Program
Select...
Related Videos
Factorising Denominator
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
Select...