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Question

A 32-digit number has all 9’s. Find the remainder when the number is divided by 111.

A
9
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B
11
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C
1
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D
99
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E
none of these
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Solution

The correct option is D 99

option d

Any number of the form aaa (3 digits) or aaaaaa (multiple of 3 digits, i.e. 6, 9 .....) is divisible by 111

Therefore group the above numbers into groups of 3 or multiples of 3.

A 32 digit number can be broken up as (3*10 digits) + (2 digits). The first part is divisible by 111. the last two digits will thus be the remainder = 99


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