Question

A $5$ m $60$ cm high vertical pole casts a shadow $3$ m $20$ cm long. Find at the same time the length of the shadow cast by another pole $10$ m $50$ cm high.

• A. $1$
• B. $6$
• C. $7$
• D. $2$

Answer 1

The correct option is B $6$

In this problem ratio of object to shadow, height is considered

According to the first condition,

$5.60:3.20$

Let the length of the shadow cast by another pole be $x$ m

According to the second condition,

$10.50:x$

Equating both the conditions

$\frac{5.60}{3.20}=\frac{10.50}{x}$

$\therefore x=\frac{10.50\times 3.20}{5.60}=\frac{5\times 5\times 2\times 3\times 7\times 2^5}{100\times 7\times 2^3}$

$\therefore x=3\times 2=6$ m

The answer is $6$ m