Question

A 5% solution of cane sugar is isotonic with 0.877 % of X. The molecular weight of substance X is:

• A. $58.98$
• B. $119.96$
• C. $95.58$
• D. $126.98$

Answer 1

Answer: (A)

$58.98$

5% solution means 100 mL solution contain 5g cane sugar
0.877 % means 100 mL solution contain 0.877g X isotonic solution $C_1=C_2$
$\frac{5}{342\times 100}=\frac{0.877}{M_w\times 100}$
$M_w=\frac{0.877}{5}\times 342=59.98$