Question

A 5 kg block has a rope of mass 2 kg attached to its underside and a 3 kg block is suspended from the other end of the rope. The whole system is accelerated upward at 2 ms−2 by an external force F0. What is the tension at middle point of the rope and F0? (g=10 ms−2)

A
48 N,100 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
48 N,120 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
100 N,120 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20 N,100 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 48 N,120 NFor calculating the value of F0, consider two blocks with the rope as a single system. F.B.D. of whole system F0−100=10×2 ⇒F0=120 N For calculating tension at the midlle point we draw F.B.D. of 3 kg block with half of the rope (mass 1 kg) as shown. So, total mass becomes 4 kg. T−4g=4(2) ⇒T=48 N

Suggest Corrections
8
Related Videos
PHYSICS
Watch in App
Explore more