CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A 500 kg boat is 9 m long and is floating without motion on still water. A man of mass 100 kg is at one end and if he runs to the other end of the boat and stops, the displacement of the boat is :


A
1.5 m in the direction of displacement of the man
loader
B
0.75 m in the direction of displacement of the man
loader
C
1.5 m in the direction opposite to the displacement of the man
loader
D
0.75 m in the direction opposite to the displacement of the man
loader

Solution

The correct option is B 1.5 m in the direction opposite to the displacement of the man
As there is no external force, the center of mass of the boat+man system remains at the same position. The displacement of boat would be in opposite direction to that of the man, to maintain same position for CoM.

Let the displacement of boat be $$x$$, in direction opposite to the displacement of man.
So net displacement of man is $$(9-x)$$

So, $$M_{man}\times(9-x) = M_{boat}\times x$$
$$\implies 100(9-x) = 500x\implies x = 900/600 = 1.5m$$

Option C is correct.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image