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Question

A 50kg skydiver falls through the air and reaches terminal velocity after some time. The drag force is a function of velocity given by
Fdrag=−bv2
where the negative sign denotes that the drag force is opposite to the direction of the velocity.
What is the terminal velocity of the skydiver (assuming the drag constant b is 0.2kg/m)?

A
5ms
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B
50ms
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C
100ms
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D
250ms
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E
2500ms
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Solution

The correct option is D 50ms
When the falling body through the air will reach to the terminal velocity, the drag force will be equal to weight of the body.
Thus, bv2=mg
The terminal velocity, v=vt=mgb=50×100.2=50m/s
Thus , option B will be correct.

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