Question

A $588c{m}^3$ volume of moist sand weighs 1010 gm. Its dry weight is 918 gm and G is 2.67. Assuming density of water as 1 gm/cc, the void ratio is

• A. 0.71

Answer 1

The correct option is A 0.71
$\gamma \left(MoistSand\right)=\frac{1010}{588}=1.717g/cc$

${\gamma }_d=\frac{918}{588}=1.561g/cc$

${\gamma }_d=\frac{G{\gamma }_w}{1+e}$

$1.561=\frac{2.67\times 1}{1+e}$

e = 0.71