A 6 m tall man finds that the angle of elevation of a 24 m high pillar and the angle of depression of its base are complementary angles. Find the distance of the man from the pillar.
The conditions given in the question can be drawn as below.
tan θ=6xtan(90−θ)=cotθ=18xSince,tanθ=1cotθ⇒x18=6x⇒x2=108⇒x=6√3 m Therefore, the distance of the man from the pillar is 6√3 m
The angle of elevation of the top of pillar from the foot of the statue is 30∘ and the angle of elevation of the top of the statue from the foot of the pillar is 60∘. If the statue is 100 m high, find the height of the pillar.
A man is standing on the deck of a ship, which is 8 m above water level. He observes the angle of elevation of the top of a hill as 60o and angle of depression of the base of the hill as 30o. What is the height of the hill?