A $60 k g$ skydiver covered a distance of $40 m$ in $2 s e c o n d s$ . The skydiver is spending a power of___KW. Take acceleration due to gravity $10 m / s^{2}$

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Solution

Given,

Mass $m$ = $60 k g$ , acceleration due to gravity $g$ = $10 m / s^{2}$

Force acting $F$ = $m g$

Displacement $s$ = $40 m$

$W o r k d o n e$ = $F o r c e \times D i s p l a c e m e n t$

$W o r k d o n e = 60 \times 10 \times 40 J$ = $24000 J$

$P o w e r$ = $\frac{w o r k d o n e}{t i m e}$

So, power spent in 2 seconds = $\frac{24000}{2}$ $= 12000 W$ $= 12 K W$

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A 60 kg skydiver covered a distance of 40 m in 2 seconds. The skydiver is spending a power of___KW. Take acceleration due to gravity 10 m/s2

Given, Mass m = 60 kg, acceleration due to gravity g = 10 m/s2 Force acting F = mg Displacement s = 40 m Work done = Force×Displacement Work done = 60×10×40 J = 24000 J Power = work donetime So, power spent in 2 seconds = 240002 =12000 W =12 KW

A $60 k g$ skydiver covered a distance of $40 m$ in $2 s e c o n d s$ . The skydiver is spending a power of___KW. Take acceleration due to gravity $10 m / s^{2}$