    Question

# A 600 W mercury lamp emits a monochromatic radiation of wavelength 331.3 nm. How many photons are emitted from the lamp per second? h=6.626×10−34 Js;velocity of light =3×108 ms−1

A
1021
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1022
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1020
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1019
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 1021According to Planck's quantum theory, E=nhcλ Where, E = energy of the radiation =600 W=600 J/s n = number of photons emitted per second h = Planck's constant =6.626×10−34 J s c = speed of light =3×108 m/s λ = wavelength of the radiation =331.3 nm=331.3×10−9m On subtituting the values in the equation and solving for n, n=Eλh.c=600×331.3×10−96.626×10−34×3×108 On solving n=1×1021 photons/second  Suggest Corrections  6      Similar questions  Related Videos   Wave Nature of Light
CHEMISTRY
Watch in App  Explore more