A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days will B finish the whole work alone?

$A$ alone can do a piece of work in $12$ days and $B$ alone can do the same work in $16$ days. They worked together on it for $3$ days and then $A$ left. How long did $B$ take to finish the remaining work?

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A and B can do a piece of work in 30 days. A alone do the work for 16 days and B alone can do the remaining work in 44 days. Then in how many days B alone do the work ?

The correct option is B 60 daysLet A's one day work =xB's one day work =y(A + B)'s one day work,x+y=130.............(1)In next condition,16x+44y=1.............(2)On solving these two equations, we getx=160 and y=160So, B can complete the work alone in 60 days.

A and B can do a piece of work in $30$ days. A alone do the work for $16$ days and B alone can do the remaining work in $44$ days. Then in how many days B alone do the work ?