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Question

A and B each throw two dice; if the sum of numbers on dice thrown by A is 9, find B's chance of throwing a higher number than A.

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Solution

B needs to throw 10,11 or 12
Now, the number of cases for throwing 10=(5,5);(6,4);(4,6)=3
Now, the number of cases for throwing 11=(5,6);(6,5)=2
Now, the number of cases for throwing 12=(6,6)=1
P(B throwing more than A)=636=16

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