$(a - b)^{2} - (a + b)^{2}$ is equal to:

2 a b

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4 a b

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6 a b

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- 4 a b

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Solution

The correct option is D $- 4 a b$
Given, $(a - b)^{2} - (a + b)^{2}$ .

We know, $(x + y)^{2} = x^{2} + 2 x y + y^{2}$
and $(x - y)^{2} = x^{2} - 2 x y + y^{2}$ .

Then,
$(a - b)^{2} - (a + b)^{2}$
$= (a^{2} + b^{2} - 2 a b) - (a^{2} + b^{2} + 2 a b)$
$= a^{2} + b^{2} - 2 a b - a^{2} - b^{2} - 2 a b)$
$= - 4 a b$ .

Therefore, option $D$ is correct.

Suggest Corrections

Similar questions

{(a - b)}^{2}

4 a b

Find:
$(a + b + c) \times (a + b - c) =$

a^{2} - 2 a b + b^{2} = (a - b)^{2}

4 a^{2} - 4 a b + b^{2}

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