The correct option is A 2(b^3 +3a^2b)(a+b)^3 (a b)^3 =(a^3 + b^3 + 3a^2 b + 3ab^2) (a^3 b^3 3a^2 b + 3ab^2) =a^3 + b^3 + 3a^2b + 3ab^2 a^3 + b^3 +3a^2 b ...

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Byju's Answer

Standard X

Mathematics

Cross-Multiplication Method of Finding Solution of a Pair of Linear Equations

a+b3-a-b3=

Question

$(a + b)^{3} - (a - b)^{3}$ =________

b^{3} + 3 a^{2} b

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2 (b^{3} + 3 a^{2} b)

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2 (a^{3} + 3 a b^{2})

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Solution

The correct option is B $2 (b^{3} + 3 a^{2} b)$
$(a + b)^{3} - (a - b)^{3}$
$= (a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2})$ - $(a^{3} - b^{3} - 3 a^{2} b + 3 a b^{2})$
$= a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2} - a^{3} + b^{3} + 3 a^{2} b - 3 a b^{2}$
$= 2 (b^{3} + 3 a^{2} b)$

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Similar questions

Expand the following formulas

(a + b)^{2}

(a - b)^{2}

(a^{2} + b^{2})

(a + b)^{3}

(a - b)^{3}

a^{3} + b^{3}

a^{3} - b^{3}

(a + b)^{3} - (a - b)^{3} = . . . . . . . . . .

{(a + b)}^{3} - {(a - b)}^{3}

Q. Solve:

(a + b)^{3} - (a - b)^{3}

Q. Evaluate:

{(a + b)}^{3} - {(a - b)}^{3}

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(a+b)3−(a−b)3 =________

The correct option is B 2(b3+3a2b)(a+b)3−(a−b)3 =(a3+b3+3a2b+3ab2)-(a3−b3−3a2b+3ab2) =a3+b3+3a2b+3ab2−a3+b3+3a2b−3ab2 =2(b3+3a2b)

$(a + b)^{3} - (a - b)^{3}$ =________

The correct option is B $2 (b^{3} + 3 a^{2} b)$
$(a + b)^{3} - (a - b)^{3}$
$= (a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2})$ - $(a^{3} - b^{3} - 3 a^{2} b + 3 a b^{2})$
$= a^{3} + b^{3} + 3 a^{2} b + 3 a b^{2} - a^{3} + b^{3} + 3 a^{2} b - 3 a b^{2}$
$= 2 (b^{3} + 3 a^{2} b)$