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Question

A, B and C are three electrolytic cells, connected in different circuits. Cell ‘A’ contains NaCl solution, and the bulb in the circuit glows brightly when the circuit is completed. Cell ‘B’ contains acetic acid in which the bulb glows dimly. Cell ‘C’ contains sugar solution inwhich the bulb does not glow. Give a reason for each observation.​ [3 Marks]

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Solution

  • Sodium chloride solution (NaCl), being a strong electrolyte, completely furnishes ions in an aqueous solution. Hence, the NaCl solution is a good conductor of electricity due to the free ions, and hence the bulb glows brighter.​ [1 Mark]
  • Acetic acid being a weak electrolyte only partially furnishes ions in an aqueous solution. So, acetic acid is a weak conductor of electricity, and hence the bulb glows dimly. [1 Mark]
  • Sugar being a non-electrolyte does not furnishes ions in an aqueous solution. So, it does not conduct electricity, and hence the bulb does not glow.​ ​[1 Mark]

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