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Question

A, B and C can alone complete a work in 15, 25 and 30 days respectively. A and B started the work and after some days A is replaced by C. Now the work is completed in a further of 6411 days. How much of the total work did B do?

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Solution

The correct option is **D** 511

Let A replaced by C after x days, so A and B worked for x days, and then B and C for 6411=7011 days.

So

(115+125)×x+(125+130)×(7011)=1

(875)×x+(715)=1

Solve, x = 5 days

So, B worked for (5+7011)=12511days

In 12511 days, B did (12511)×(125)=511 of the total work.

Let A replaced by C after x days, so A and B worked for x days, and then B and C for 6411=7011 days.

So

(115+125)×x+(125+130)×(7011)=1

(875)×x+(715)=1

Solve, x = 5 days

So, B worked for (5+7011)=12511days

In 12511 days, B did (12511)×(125)=511 of the total work.

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