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Question

A. B and C can do a piece of work in 15, 12 and 20 days respectively. They started the work together. but C left after 2 days. In how many days will the remaining work he completed by A and B?


Solution

A's one day's work =115

B's one day's work =112

C's one day's work =120

A,B and C's one day's work 

=115+112+120

=4+5+360 (LCM of 15,12,20=60)

=1260=15

A,B and C's 2 days work =15×2=25

Remaining work =125

=525=35 A and B's one days work =115+112

=4+560=960=320

A and B will do the remaining work 35in=203×35=4 days

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