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Question

a,b are positive integers. If 21ab2 and 15ab are perfect squares, the minimum value of a + b is


A

56

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B

65

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C

23

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D

42

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Solution

The correct option is A

56


1.If p is a factor of a perfect square, then p2 must also be a factor, where p is a prime.

21ab2 = 3.7.ab2

b2 is a perfect square. So the smallest value of a is 3 x 7,

a = 3 x 7 = 21

15 ab = 3.5.a.b

= 3.5.3.7.b

∴ The smallest value of b is 5 x 7 = 35.

∴ a + b = 21 + 35= 56


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